Python **kwargs 的實測  

都必填

都有帶入值

def test_func(a1, a2):
    print(a1)
    print(a2)


if __name__ == '__main__':
    d = dict()
    d['a1'] = 1
    d['a2'] = 2

    test_func(**d)

out put

1
2

有值未帶入

def test_func(a1, a2):
    print(a1)
    print(a2)


if __name__ == '__main__':
    d = dict()
    d['a1'] = 1

    test_func(**d)

out put

Traceback (most recent call last):
  File "xxx/main.py", line 44, in <module>
    test_func(**d)
TypeError: test_func() missing 1 required positional argument: 'a2'

有預設值參數

def test_func(a1, a2=None):
    print(a1)
    print(a2)


if __name__ == '__main__':
    d = dict()
    d['a1'] = 1

    test_func(**d)

output

1
None

帶入沒有該參數的key & value (unexpected-keyword-arguments)

def test_func(a1, a2=None):
    print(a1)
    print(a2)


if __name__ == '__main__':
    d = dict()
    d['a1'] = 1
    d['a2'] = 2
    d['a3'] = 3

    test_func(**d)

output

Traceback (most recent call last):
  File "xxx/main.py", line 46, in <module>
    test_func(**d)
TypeError: test_func() got an unexpected keyword argument 'a3'

解決unexpected-keyword-arguments 的作法

適用於向下相容

def test_func(a1, a2=None,**kwargs):
    print(a1)
    print(a2)
    print(kwargs['a3'])


if __name__ == '__main__':
    d = dict()
    d['a1'] = 1
    d['a2'] = 2
    d['a3'] = 3

    test_func(**d)

output

1
2
3

md